Sorcerous Stabber Orphen: Battle of Kimluck

Season 1 Episode 11: The Uoar Class

4 Seasons Mar 17, 2020 TV-14 23m 5.6

Claiomh tries to cook some food to nurse Orphen back to health, but it might be doing more harm than good. Orphen and Leticia take Majic to the Tower of Fangs so he can enroll.

Season 1 Episodes:

Episode 1 A Vestige of the Past

1. A Vestige of the Past

Aired: Jan 7, 2020

Orphen is searching for his friend Azalie after she had disappeared five year...

Episode 2 The Tower of Fangs

2. The Tower of Fangs

Aired: Jan 14, 2020

Orphen, Volkan, and Dortin are captured by the authorities after the fiasco w...

Episode 3 Heed My Call, Beast

3. Heed My Call, Beast

Aired: Jan 21, 2020

Orphen goes with Childman and the other Black Sorcerers in order to try to tr...

Episode 5 Deep Dragon

5. Deep Dragon

Aired: Feb 4, 2020

Orphen, Claiomh, and Majic try to get through Fenrir's Forest to get to Tafre...

Episode 6 Forest Maiden

6. Forest Maiden

Aired: Feb 11, 2020

After Orphen is attacked by the Deep Dragon, he wakes up in a cell unsure of ...

Episode 9 Ghost from the Past

9. Ghost from the Past

Aired: Mar 3, 2020

Leticia and Orphen try to figure out who the assassin actually is. Is Orphen ...

Episode 11 The Uoar Class

11. The Uoar Class

Aired: Mar 17, 2020

Claiomh tries to cook some food to nurse Orphen back to health, but it might ...

Episode 12 Death Keening

12. Death Keening

Aired: Mar 24, 2020

Tish ends up following one of the assassins so that Orphen wouldn't have to d...

Watch Now

Streaming in:

United States flag


Info about Sorcerous Stabber Orphen: Battle of Kimluck

Current Status: Ended

Network: AT-X

Production Country: Japan

Genres: Drama, Adventure, Animation, Fantasy, Action

Sorcerous Stabber Orphen: Battle of Kimluck: Where to Watch Online?

Currently you are able to watch "Sorcerous Stabber Orphen: Battle of Kimluck" streaming on Hulu, Funimation, Crunchyroll Premium. It is also possible to rent or buy on Windows Store, Amazon, Google Play, AppleTV, YouTube online.